A=Infantile botulism
B=Kid eats honey
P(A|!B) = P(A) * (1 - P(B|A))
Not sure it is correct!
The ACX signature says:
P(A|B) = [P(A)*P(B|A)]/P(B)
So
P(A|!B) = [P(A)*P(!B|A)]/P(!B)
= (1/40000) * .8 / ???
??? Is very small though if people take the medical advice.
Their number assumes nobody follows the advice!
A=Infantile botulism
B=Kid eats honey
P(A|!B) = P(A) * (1 - P(B|A))
Not sure it is correct!
The ACX signature says:
P(A|B) = [P(A)*P(B|A)]/P(B)
So
P(A|!B) = [P(A)*P(!B|A)]/P(!B)
= (1/40000) * .8 / ???
??? Is very small though if people take the medical advice.
Their number assumes nobody follows the advice!