Of course, this is nitpicking :). For all practical purpose, this O(log n) is O(1).
If you are interested, I can try to recover the proof that the rotation step can be done in O(n), thus allowing to apply the master theorem on the main recursion and getting the O(n log n) result.
But that's such an effort in futility that I refuse to do so. So it's theoretically and practically in-place, but not technically.